Lesson 1
Problem:
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4 ) 948
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Solution
Step 1:
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Saying the
table of 4 to reach 9, we know that 2 times 4 is
9. So, we write 2 in the quotient and 8 under
9.
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Solution
Step 2:
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On subtraction, we get 1 as remainder and bringing down
4, we get 14.
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Solution
Step 3:
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Now, 3 times 4 is 12. So, we
write 12 under 14 and 3 in the quotient.
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Solution
Step 4:
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On subtraction, we get 2 as remainder and bringing down
8, we get 28.
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Solution
Step 5:
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Now, 7 times 4 is 28. So, we
write 28 under 28 and 7 in the quotient.
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Solution
Step 6:
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On subtraction, we get 0 as the final remainder.
Quotient=237, remainder=0
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