Triple Digit Division - No Remainders |
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Lesson 1 |
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Problem
Step 1: As the divisor 4 is larger than 1 we shall take 1 along with 1.We know that 4 can go into 11 equally 2 times. So we write 2 in the quotient and under 11 we write 8.
Step 2: On subtraction we get 3 asthe remainder and bring down the 2. 8 times 4 are 32. So we subtract 32 from 32 and hence the remainder is 0.
Step 3: Answer: 28 Two practice problems
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